x=1/32(y-1)^2-4

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Solution for x=1/32(y-1)^2-4 equation: 


x in (-oo:+oo)

x = (1/32)*(y-1)^2-4 // - (1/32)*(y-1)^2-4

x-((1/32)*(y-1)^2)+4 = 0

(-1/32)*(y-1)^2+x+4 = 0

x-1/32*(y-1)^2+4 = 0

x-1/32*(y-1)^2+4 = 0

x-1/32*y^2+1/16*y-1/32+4 = 0

x-1/32*y^2+1/16*y+127/32 = 0

x-1/32*y^2+1/16*y+127/32 = 0

x-1/32*y^2+1/16*y+127/32 = 0 // - 1/16*y-1/32*y^2+127/32

x = -(1/16*y-1/32*y^2+127/32)

x = -(1/16*y-1/32*y^2+127/32)

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